-0.3t^2+3t=6.2

Solution for -0.3t^2+3t=6.2 equation:

-0.3t^2+3t=6.2

We move all terms to the left:

-0.3t^2+3t-(6.2)=0

We add all the numbers together, and all the variables

-0.3t^2+3t-6.2=0

a = -0.3; b = 3; c = -6.2;
Δ = b2-4ac
Δ = 32-4·(-0.3)·(-6.2)
Δ = 1.56
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{1.56}}{2*-0.3}=\frac{-3-\sqrt{1.56}}{-0.6}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{1.56}}{2*-0.3}=\frac{-3+\sqrt{1.56}}{-0.6}
$